3z^2+30z+72=0

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Solution for 3z^2+30z+72=0 equation: 



3z^2+30z+72=0

a = 3; b = 30; c = +72;
Δ = b2-4ac
Δ = 302-4·3·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*3}=\frac{-36}{6}
=-6
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*3}=\frac{-24}{6}
=-4
$

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